-[8z-(10z+3)]=3+(1z+9)

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Solution for -[8z-(10z+3)]=3+(1z+9) equation:


Simplifying
-1[8z + -1(10z + 3)] = 3 + (1z + 9)

Reorder the terms:
-1[8z + -1(3 + 10z)] = 3 + (1z + 9)
-1[8z + (3 * -1 + 10z * -1)] = 3 + (1z + 9)
-1[8z + (-3 + -10z)] = 3 + (1z + 9)

Reorder the terms:
-1[-3 + 8z + -10z] = 3 + (1z + 9)

Combine like terms: 8z + -10z = -2z
-1[-3 + -2z] = 3 + (1z + 9)
[-3 * -1 + -2z * -1] = 3 + (1z + 9)
[3 + 2z] = 3 + (1z + 9)

Reorder the terms:
3 + 2z = 3 + (9 + 1z)

Remove parenthesis around (9 + 1z)
3 + 2z = 3 + 9 + 1z

Combine like terms: 3 + 9 = 12
3 + 2z = 12 + 1z

Solving
3 + 2z = 12 + 1z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
3 + 2z + -1z = 12 + 1z + -1z

Combine like terms: 2z + -1z = 1z
3 + 1z = 12 + 1z + -1z

Combine like terms: 1z + -1z = 0
3 + 1z = 12 + 0
3 + 1z = 12

Add '-3' to each side of the equation.
3 + -3 + 1z = 12 + -3

Combine like terms: 3 + -3 = 0
0 + 1z = 12 + -3
1z = 12 + -3

Combine like terms: 12 + -3 = 9
1z = 9

Divide each side by '1'.
z = 9

Simplifying
z = 9

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